The hybridisation and unpaired electrons in [ | vedclass

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Question

(A) The central metal ion is $Fe^{2+}$,which has an electronic configuration of $[Ar] 3d^6$.$H_2O$ is a weak field ligand,so it does not cause pairing

Vedclass · Accepted Answer

$sp^3d^2 ; 4$

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(A) The central metal ion is $Fe^{2+}$,which has an electronic configuration of $[Ar] 3d^6$.$H_2O$ is a weak field ligand,so it does not cause pairing of electrons in the $3d$ orbital.Thus,the $3d$ electrons are arranged as $t_{2g}^4 e_g^2$,resulting in $4$ unpaired electrons.The hybridization involves the outer $4d$ orbitals,leading to $sp^3d^2$ hybridization (outer orbital complex).

The hybridisation and unpaired electrons in $[Fe(H_2O)_6]^{2+}$ ion are:

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