The hydrogen ion concentration of a 0.006 M | vedclass

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(B) For a weak acid,the dissociation is given by: $C_6H_5COOH \rightleftharpoons C_6H_5COO^- + H^+$The dissociation constant $K_a$ is given by $K_a =

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$6 	imes 10^{-4}$

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(B) For a weak acid,the dissociation is given by: $C_6H_5COOH ightleftharpoons C_6H_5COO^- + H^+$The dissociation constant $K_a$ is given by $K_a = \frac{[H^+][C_6H_5COO^-]}{[C_6H_5COOH]} \approx C\alpha^2$.Given $C = 0.006 \ M$ and $K_a = 6 	imes 10^{-5}$.The degree of dissociation $\alpha = \sqrt{\frac{K_a}{C}} = \sqrt{\frac{6 	imes 10^{-5}}{0.006}} = \sqrt{10^{-2}} = 0.1$.The hydrogen ion concentration $[H^+] = C\alpha = 0.006 	imes 0.1 = 6 	imes 10^{-4} \ M$.

The hydrogen ion concentration of a $0.006 \ M$ benzoic acid solution is $(K_a = 6 \times 10^{-5})$

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