$K_b$ for $NH_4OH$ is $1.8 \times 10^{-5}$. The $[OH^{-}]$ of $0.1 \ M \ NH_4OH$ is
- A$5.0 \times 10^{-2}$
- B$4.20 \times 10^{-3}$
- C$1.34 \times 10^{-3}$
- D$1.8 \times 10^{-6}$
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