The intensity ratio of the maxima and minima in an interference pattern produced by two coherent sources of light is $9: 1$. The intensities of the light sources used are in the ratio (in $: 1$)

The ratio of intensities of two waves is $9 : 1$. They are producing interference. The ratio of maximum and minimum intensities will be

Consider an $YDSE$ that has different slit widths. As a result,the amplitudes of waves from the two slits are $A$ and $2A$,respectively. If $I_0$ is the maximum intensity of the interference pattern,then the intensity of the pattern at a point where the phase difference between the waves is $\phi$ is:

In Young's double-slit experiment,the intensity at a point where the path difference is $\lambda$ is $k$. What will be the intensity at a point where the path difference is $\lambda/4$? ($\lambda$ = wavelength of light)

Obtain the formula for the intensity of light if the phase difference at a point from two coherent sources is $\phi$.

Two coherent sources of intensity ratio $\alpha$ interfere. The value of $\frac{I_{max} - I_{min}}{I_{max} + I_{min}}$ is