The intercept cut off from the y-axis is twic | vedclass

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(A) Let the $x$-intercept be $a$ and the $y$-intercept be $2a$. The intercept form of the line equation is $\frac{x}{a} + \frac{y}{2a} = 1$. Since the

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$2x + y = 4$

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(A) Let the $x$-intercept be $a$ and the $y$-intercept be $2a$. The intercept form of the line equation is $\frac{x}{a} + \frac{y}{2a} = 1$. Since the line passes through $(1, 2)$,we substitute these coordinates into the equation: $\frac{1}{a} + \frac{2}{2a} = 1$ $\frac{1}{a} + \frac{1}{a} = 1$ $\frac{2}{a} = 1 \implies a = 2$. Substituting $a = 2$ back into the intercept form equation: $\frac{x}{2} + \frac{y}{4} = 1$ Multiplying by $4$,we get $2x + y = 4$.

The intercept cut off from the $y$-axis is twice that from the $x$-axis by a line,and the line passes through $(1, 2)$. Find its equation.

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