The ionic radius of Cr is minimum in which of | vedclass

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(A) The oxidation state of $Cr$ in the given compounds is calculated as follows:$1. 	ext{ In } CrCl_3, 	ext{ the oxidation state of } Cr 	ext{ is }

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$K_2CrO_4$

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(A) The oxidation state of $Cr$ in the given compounds is calculated as follows:$1. 	ext{ In } CrCl_3, 	ext{ the oxidation state of } Cr 	ext{ is } +3$.$2. 	ext{ In } CrF_3, 	ext{ the oxidation state of } Cr 	ext{ is } +3$.$3. 	ext{ In } CrO_2, 	ext{ the oxidation state of } Cr 	ext{ is } +4$.$4. 	ext{ In } K_2CrO_4, 	ext{ the oxidation state of } Cr 	ext{ is } +6$.As the ionic radius of an ion decreases with an increase in its positive oxidation state (due to increased effective nuclear charge),the $Cr$ ion with the highest oxidation state will have the minimum ionic radius.Since $Cr$ has the maximum oxidation state of $+6$ in $K_2CrO_4$,it has the minimum ionic radius among the given compounds.

The ionic radius of $Cr$ is minimum in which of the following compounds?

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