The kinetic energy of an electron revolving a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an electron revolving in an orbit around a nucleus,the total energy $E$,kinetic energy $K.E.$,and potential energy $P.E.$ are related as follo

Vedclass · Accepted Answer

Half of its $P.E.$

Vedclass · Answer

(D) For an electron revolving in an orbit around a nucleus,the total energy $E$,kinetic energy $K.E.$,and potential energy $P.E.$ are related as follows:$K.E. = -E$$P.E. = 2E$From these relations,we can see that $K.E. = -\frac{1}{2} P.E.$In terms of magnitude,the kinetic energy is half of the potential energy.$|K.E.| = \frac{1}{2} |P.E.|$Therefore,the kinetic energy is half of its $P.E.$

The kinetic energy of an electron revolving around a nucleus will be

Similar Questions

$A$ hydrogen atom at rest emits a photon during its transition from $n = 2$ to $n = 1$. Choose the $INCORRECT$ statement.

The ratio between the total acceleration of the electron in a singly ionized helium atom and a hydrogen atom (both in the ground state) is:

The product of angular speed and tangential speed of an electron in the $n^{\text{th}}$ orbit of a hydrogen atom is:

The angular momentum of an electron in the $n^{th}$ orbit is given by:

According to Bohr's atomic model,which of the following is $NOT$ a possible energy for a photon emitted by a hydrogen atom (in $;eV$)? (in $eV$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module