The lanthanoid that would show color is

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(D) The color of lanthanoid ions depends on the presence of unpaired $f$-electrons. $La^{3+}$ has a configuration of $[Xe] 4f^0$ (no unpaired electron

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$Sm^{3+}$

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(D) The color of lanthanoid ions depends on the presence of unpaired $f$-electrons. $La^{3+}$ has a configuration of $[Xe] 4f^0$ (no unpaired electrons). $Gd^{3+}$ has a configuration of $[Xe] 4f^7$ (half-filled,stable,but colorless in many compounds due to high energy transition). $Lu^{3+}$ has a configuration of $[Xe] 4f^{14}$ (fully filled,no unpaired electrons). $Sm^{3+}$ has a configuration of $[Xe] 4f^5$,which contains unpaired electrons,allowing for $f-f$ transitions that result in a yellow color.

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