The least integral value $\alpha$ of $x$ such that $\frac{x - 5}{x^2 + 5x - 14} > 0$ satisfies:

  • A
    $\alpha^2 + 3\alpha - 4 = 0$
  • B
    $\alpha^2 - 5\alpha + 4 = 0$
  • C
    $\alpha^2 - 7\alpha + 6 = 0$
  • D
    $\alpha^2 + 5\alpha - 6 = 0$

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