The length of a diagonal of a square is 8 sqr | vedclass

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(C) Let the side of the square be $a$.The length of the diagonal of a square is given by the formula $d = a \sqrt{2}$.Given that the diagonal $d = 8 \

Vedclass · Accepted Answer

$64$

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(C) Let the side of the square be $a$.The length of the diagonal of a square is given by the formula $d = a \sqrt{2}$.Given that the diagonal $d = 8 \sqrt{2}$.Equating the two,we get $a \sqrt{2} = 8 \sqrt{2}$.Dividing both sides by $\sqrt{2}$,we find the side length $a = 8$.The area of a square is calculated as $	ext{Area} = a^2$.Substituting the value of $a$,we get $	ext{Area} = 8^2 = 64$.Alternatively,the area of a square can be calculated using the diagonal $d$ as $	ext{Area} = \frac{1}{2} 	imes d^2$.Substituting $d = 8 \sqrt{2}$,we get $	ext{Area} = \frac{1}{2} 	imes (8 \sqrt{2})^2 = \frac{1}{2} 	imes (64 	imes 2) = \frac{1}{2} 	imes 128 = 64$.

The length of a diagonal of a square is $8 \sqrt{2}$. Then,its area is $\ldots \ldots \ldots$

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