The length of a rectangle is 2 , cm more than | vedclass

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Question

(C) Let the breadth of the rectangle be $x \, cm$.Then,the length of the rectangle is $(x + 2) \, cm$.The perimeter of a rectangle is given by the for

Vedclass · Accepted Answer

$143$

Vedclass · Answer

(C) Let the breadth of the rectangle be $x \, cm$.Then,the length of the rectangle is $(x + 2) \, cm$.The perimeter of a rectangle is given by the formula $P = 2 	imes (	ext{length} + 	ext{breadth})$.Given $P = 48 \, cm$,we have $2(x + x + 2) = 48$.Dividing by $2$,we get $2x + 2 = 24$.Subtracting $2$ from both sides,$2x = 22$,which gives $x = 11 \, cm$.So,the breadth is $11 \, cm$ and the length is $11 + 2 = 13 \, cm$.The area of the rectangle is $	ext{length} 	imes 	ext{breadth} = 13 \, cm 	imes 11 \, cm = 143 \, cm^2$.

The length of a rectangle is $2 \, cm$ more than its breadth. The perimeter is $48 \, cm$. The area of the rectangle (in $cm^2$) is?

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