The length of a rectangle is 2,cm less than 3 | vedclass

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(C) Let the breadth of the rectangle be $x\,cm$.Then,by the given condition,the length of the rectangle is $(3x - 2)\,cm$.Now,by the data,the area of

Vedclass · Accepted Answer

$28$

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(C) Let the breadth of the rectangle be $x\,cm$.Then,by the given condition,the length of the rectangle is $(3x - 2)\,cm$.Now,by the data,the area of the rectangle is $280\,cm^2$.$	herefore$ Area of rectangle $= 280$$	herefore$ Length $	imes$ Breadth $= 280$$	herefore (3x - 2)(x) = 280$$	herefore 3x^2 - 2x = 280$$	herefore 3x^2 - 2x - 280 = 0$$	herefore (3x + 28)(x - 10) = 0$$	herefore 3x + 28 = 0$ or $x - 10 = 0$$	herefore x = -\frac{28}{3}$ or $x = 10$As $x$ is the breadth of a rectangle,it cannot be negative.$	herefore x = -\frac{28}{3}$ is not possible.$	herefore x = 10$Now,the length of the rectangle $= 3x - 2 = 3(10) - 2 = 28\,cm$.Hence,the length of the given rectangle is $28\,cm$.

The length of a rectangle is $2\,cm$ less than $3$ times its breadth. If its area is $280\,cm^2$,then find its length.

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