(A) The principle of a potentiometer states that the potential drop across a length $l$ of the wire is directly proportional to the length,provided th

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(A) The principle of a potentiometer states that the potential drop across a length $l$ of the wire is directly proportional to the length,provided the current $i$ in the potentiometer wire remains constant.$V = kl$,where $k$ is the potential gradient $(k = \frac{E}{L})$.Given: $L = 100 \, cm$,$E = emf$ of the standard cell,$l = 30 \, cm$.The $emf$ of the battery being measured is $V = \frac{E}{L} \times l$.Substituting the values: $V = \frac{E}{100} \times 30 = \frac{30E}{100}$.Note: At the balance point,no current flows through the battery being measured,so its internal resistance does not affect the reading.

Class 12 Physics Current Electricity Potentiometer

Medium

The length of a wire of a potentiometer is $100 \, cm$,and the $emf$ of its standard cell is $E \, volt$. It is employed to measure the $emf$ of a battery whose internal resistance is $0.5 \, \Omega$. If the balance point is obtained at $l = 30 \, cm$ from the positive end,the $emf$ of the battery is (where $i$ is the current in the potentiometer wire).

AIEEE 2003 All AIEEE

A
$\frac{30E}{100}$
B
$\frac{30E}{100.5}$
C
$\frac{30E}{100 - 0.5}$
D
$\frac{30(E - 0.5i)}{100}$

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Current Electricity

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Potentiometer

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$A$ battery of $6\,V$ is connected to the terminals of a $3\,m$ long wire of uniform thickness and resistance of the order of $100\,\Omega$. The difference of potential between two points separated by $50\,cm$ on the wire will be .......... $V$.

EasyAIPMT 2004

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$A$ potentiometer is used to measure the potential difference between $A$ and $B$. The null point is obtained at $0.9 \ m$. Now,the potential difference between $A$ and $C$ is measured,and the null point is obtained at $0.3 \ m$. The ratio $\frac{E_2}{E_1}$ is $\left(E_1 > E_2\right)$.

MediumMHT CET 2022

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$A$ potentiometer wire has a length of $100 \ cm$ and is connected to a cell of $emf \ E$. It is used to measure the $emf \ E_0$ of a battery with an internal resistance of $0.5 \ \Omega$. If the balance point is obtained at a distance of $\ell = 30 \ cm$ from the positive terminal,the $emf \ E_0$ of the battery is:

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$A$ potentiometer wire is $4 \text{ m}$ long and a potential difference of $2 \text{ V}$ is maintained between its ends. The e.m.f. of the cell which balances against a length of $80 \text{ cm}$ of the potentiometer wire is: (in $\text{ V}$)

DifficultMHT CET 2026

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$A$ cell of $emf$ $2 \,V$ and internal resistance $5 \,\Omega$ is connected to a wire of length $100 \,cm$ and resistance $15 \,\Omega$. What is the potential gradient along the wire (in $,V/cm$)?

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$A$ battery of $6\,V$ is connected to the terminals of a $3\,m$ long wire of uniform thickness and resistance of the order of $100\,\Omega$. The difference of potential between two points separated by $50\,cm$ on the wire will be .......... $V$.

$A$ potentiometer is used to measure the potential difference between $A$ and $B$. The null point is obtained at $0.9 \ m$. Now,the potential difference between $A$ and $C$ is measured,and the null point is obtained at $0.3 \ m$. The ratio $\frac{E_2}{E_1}$ is $\left(E_1 > E_2\right)$.

$A$ potentiometer wire is $4 \text{ m}$ long and a potential difference of $2 \text{ V}$ is maintained between its ends. The e.m.f. of the cell which balances against a length of $80 \text{ cm}$ of the potentiometer wire is: (in $\text{ V}$)

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