The length of the tube of a microscope is 10 | vedclass

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(D) The magnifying power $m$ of a compound microscope for a final image formed at the near point $(D = 25 \, cm)$ is given by the formula:$m \simeq \f

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$500$

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(D) The magnifying power $m$ of a compound microscope for a final image formed at the near point $(D = 25 \, cm)$ is given by the formula:$m \simeq \frac{L \cdot D}{f_o \cdot f_e}$Where:$L = 10 \, cm$ (tube length)$D = 25 \, cm$ (least distance of distinct vision)$f_o = 0.5 \, cm$ (focal length of objective lens)$f_e = 1.0 \, cm$ (focal length of eye lens)Substituting the values:$m = \frac{10 	imes 25}{0.5 	imes 1.0} = \frac{250}{0.5} = 500$.

The length of the tube of a microscope is $10 \, cm$. The focal lengths of the objective and eye lenses are $0.5 \, cm$ and $1.0 \, cm$ respectively. The magnifying power of the microscope is about:

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