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(D) The intensity of the resultant wave in an interference pattern is given by the formula: $I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} \cos \phi$.For max

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$4 I_{0}$

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(D) The intensity of the resultant wave in an interference pattern is given by the formula: $I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} \cos \phi$.For maxima,the phase difference $\phi = 2n\pi$,so $\cos \phi = 1$.Thus,$I_{\max} = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} = (\sqrt{I_{1}} + \sqrt{I_{2}})^2$.Given $I_{1} = I_{2} = I_{0}$,we substitute these values into the formula:$I_{\max} = (\sqrt{I_{0}} + \sqrt{I_{0}})^2 = (2\sqrt{I_{0}})^2 = 4I_{0}$.

The light waves from two coherent sources have same intensity $I_{1} = I_{2} = I_{0}$. In the interference pattern,the intensity of light at minima is zero. What will be the intensity of light at maxima?

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