The line $\frac{x + 1}{2} = \frac{y + 1}{3} = \frac{z + 1}{4}$ meets the plane $x + 2y + 3z = 14$ at the point:

  • A
    $(1, 2, 3)$
  • B
    $(3, 2, -5)$
  • C
    $(2, 0, 4)$
  • D
    $(3, -2, 5)$

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