The locus of a point such that the sum of its | vedclass

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(B) Let the two perpendicular lines be the coordinate axes $OX$ and $OY$.Let $P(x, y)$ be the point whose locus is required.Since $P$ is in the first

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$x + y = 2$

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(B) Let the two perpendicular lines be the coordinate axes $OX$ and $OY$.Let $P(x, y)$ be the point whose locus is required.Since $P$ is in the first quadrant,$x > 0$ and $y > 0$.The distance of $P(x, y)$ from the $Y$-axis $(OY)$ is $x$,and the distance from the $X$-axis $(OX)$ is $y$.According to the problem,the sum of these distances is $2$ units:$x + y = 2$Since the point is in the first quadrant,the locus is the line segment $x + y = 2$ where $x > 0$ and $y > 0$.

The locus of a point such that the sum of its distances from two given perpendicular lines is equal to $2$ units in the first quadrant is

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