The logic behind the NOR gate is that it give | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $NOR$ gate is a combination of an $OR$ gate followed by a $NOT$ gate. The Boolean expression for an $OR$ gate is $Y = A + B$. The Boolean expr

Vedclass · Accepted Answer

High output when both the inputs are low

Vedclass · Answer

(A) The $NOR$ gate is a combination of an $OR$ gate followed by a $NOT$ gate. The Boolean expression for an $OR$ gate is $Y = A + B$. The Boolean expression for a $NOR$ gate is $Y = \overline{A + B}$. According to this expression, if both inputs $A$ and $B$ are $0$ (low), then $Y = \overline{0 + 0} = \overline{0} = 1$ (high). If any input is $1$ (high), the output becomes $0$ (low). Therefore, the $NOR$ gate gives a high output only when both inputs are low.

The logic behind the $NOR$ gate is that it gives

Similar Questions

In the following circuit,the output $Y$ for all possible inputs $A$ and $B$ is expressed by the truth table.

The output of the following combination is the same as that of:

Justify the output waveform $(Y)$ of the $OR$ gate for the following inputs $A$ and $B$ given in the figure.

Four logic gate symbols are given below. Which of these are the symbols for $OR$,$NOR$,and $NAND$ gates,respectively?

Draw the output signal $Y$ for the given combination of logic gates shown in the figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module