The logically equivalent statement of (sim p | vedclass

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(B) Given expression: $(\sim p \wedge q) \vee (\sim p \wedge \sim q) \vee (p \wedge \sim q)$ Using the distributive law on the first two terms: $(\sim

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$(\sim p) \vee (\sim q)$

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(B) Given expression: $(\sim p \wedge q) \vee (\sim p \wedge \sim q) \vee (p \wedge \sim q)$ Using the distributive law on the first two terms: $(\sim p \wedge (q \vee \sim q)) \vee (p \wedge \sim q)$ Since $(q \vee \sim q) \equiv T$ (Tautology),the expression becomes: $(\sim p \wedge T) \vee (p \wedge \sim q)$ This simplifies to: $(\sim p) \vee (p \wedge \sim q)$ Applying the distributive law again: $(\sim p \vee p) \wedge (\sim p \vee \sim q)$ Since $(\sim p \vee p) \equiv T$,the expression becomes: $T \wedge (\sim p \vee \sim q)$ Therefore,the final equivalent statement is: $(\sim p) \vee (\sim q)$

The logically equivalent statement of $(\sim p \wedge q) \vee (\sim p \wedge \sim q) \vee (p \wedge \sim q)$ is

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