The magnetic flux linked with a vector area $\overrightarrow{A}$ in a uniform magnetic field $\overrightarrow{B}$ is

  • A
    $\overrightarrow{B} \times \overrightarrow{A}$
  • B
    $AB$
  • C
    $\overrightarrow{B} \cdot \overrightarrow{A}$
  • D
    $\frac{B}{A}$

Explore More

Similar Questions

$A$ uniform magnetic field of strength $B=2 \text{ mT}$ exists vertically downwards. These magnetic field lines pass through a closed surface as shown in the figure. The closed surface consists of a hemisphere $S_1$,a right circular cone $S_2$,and a circular surface $S_3$. The magnetic flux through $S_1$ and $S_2$ are respectively:

Assertion $(A)$: Magnetic flux is a vector quantity.
Reason $(R)$: Value of magnetic flux can be positive, negative, or zero.

$A$ square loop of side $2 \ m$ lies in the $Y-Z$ plane in a region having a magnetic field $\vec{B}=(5 \hat{i}+3 \hat{j}-4 \hat{k}) \ T$. The magnitude of magnetic flux through the square loop is (in $Wb$)

The figure represents an area $A = 0.5\,m^2$ situated in a uniform magnetic field $B = 2.0\,Wb/m^2$. The area makes an angle of $60^o$ with the magnetic field. The value of the magnetic flux through the area is equal to......$Wb$.

Which of the following statements regarding magnetic lines of force is correct?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo