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(D) The power of the combination of lenses is given by $P = P_1 + P_2 = 20\,D - 4\,D = 16\,D$.The focal length $f$ of the combination is $f = \frac{1}

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$10$

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(D) The power of the combination of lenses is given by $P = P_1 + P_2 = 20\,D - 4\,D = 16\,D$.The focal length $f$ of the combination is $f = \frac{1}{P} = \frac{1}{16}\,m = \frac{100}{16}\,cm = 6.25\,cm$.The magnification $m$ for a magnifying glass when the image is formed at the least distance of distinct vision $D = 25\,cm$ is given by $m = 1 + \frac{D}{f}$.Substituting the values,$m = 1 + \frac{25}{6.25} = 1 + 4 = 5$.The size of the image $h'$ is given by $h' = m 	imes h$,where $h = 2\,cm$ is the height of the object.Therefore,$h' = 5 	imes 2\,cm = 10\,cm$.

$A$ magnifying glass is made of a combination of lenses with power $+20\,D$ and $-4\,D$. If the least distance of distinct vision is $25\,cm$,calculate the size of an image of an object $2\,cm$ high seen through the magnifying glass. (in $,cm$)

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