The magnitude of the earth's magnetic field at a place is $B_0$ and the angle of dip is $\delta$. $A$ horizontal conductor of length $l$ lying along the magnetic north-south moves eastwards with a velocity $v$. The emf induced across the conductor is

$A$ conducting rod $PQ$ of length $L = 1.0 \, m$ is moving with a uniform speed $v = 2 \, m/s$ in a uniform magnetic field $B = 4.0 \, T$ directed into the paper. $A$ capacitor of capacity $C = 10 \, \mu F$ is connected as shown in the figure. Then:

$A$ rod of length $l$ is rotating with constant angular velocity $\omega$ in a uniform magnetic field $B$ perpendicular to the plane of rotation. The rod is marked at points $0, 1, 2, \dots, 8$ at equal spacing. What is the nature of the potential difference between consecutive points as we move from left to right?

$A$ conducting rod is moving towards the right with a velocity '$V$' in a uniform magnetic field '$B$'. If the direction of the induced current '$i$' is as shown in the figure, then the direction of '$B$' is:

$A$ rectangular loop with a sliding connector of length $l = 1.0 \, m$ is situated in a uniform magnetic field $B = 2 \, T$ perpendicular to the plane of the loop. The resistance of the connector is $r = 2 \, \Omega$. Two resistors of $6 \, \Omega$ and $3 \, \Omega$ are connected as shown in the figure. The external force required to keep the connector moving with a constant velocity $v = 2 \, m/s$ is ........ $N$.

The radius of a circular loop placed in a perpendicular uniform magnetic field is increasing at a constant rate of $r_0 \ m s^{-1}$. If at any instant the radius of the loop is $r$,then the emf induced in the loop at that instant will be: