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(C) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ followed by acidification $(H^+)$,which is the Kolbe-

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(C) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ followed by acidification $(H^+)$,which is the Kolbe-Schmitt reaction. This yields salicylic acid ($2$-hydroxybenzoic acid) as intermediate $A$.$2$. Salicylic acid then reacts with acetic anhydride $(CH_3CO)_2O$ (acetylation of the phenolic -$OH$ group) to form acetylsalicylic acid,commonly known as Aspirin.

The main product of the following reaction will be:

Similar Questions

The acidity of the following compounds follows the order:
$I$: Phenol
$II$: $p$-Methoxyphenol
$III$: $p$-Nitrophenol
$IV$: $m$-Nitrophenol

Which reaction is used to prepare $2$-hydroxybenzaldehyde from phenol?

Identify compound $(Z)$ in the following reaction sequence.

Describe the reactions of nitration and bromination of phenol.

The order of reactivity of phenol $(I)$,nitrobenzene $(II)$,and benzene $(III)$ towards nitration is:

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