The major product formed in the following reaction is :

  • A
    $CH_3-C(CH_3)=CH-CH_2CH_3$
  • B
    $CH_3-C(CH_3)=C(CH_3)_2$
    Option B
  • C
    $CH_3-C(CH_3)=CH-CH_3$
  • D
    $CH_3-C(CH_3)_2-CH=CH_2$

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Propanal and pentan-$3$-one are the ozonolysis products of an alkene. What is the structural formula of the alkene?

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Alkenes react with water in the presence of acid to form alcohols. Identify the steps involved in the mechanism of the reaction from the following :
a) Nucleophilic addition of hydroxide ion to alkene
b) Protonation of alkene by electrophilic attack of $H_3O^{+}$
c) Electrophilic attack of $H_2O$ on carbanion
d) Nucleophilic attack of $H_2O$ on carbocation
e) Loss of $^{\ominus}OH$ to form an alcohol
f) Loss of $H^{\oplus}$ to form an alcohol

$X$ in the above reaction is

The addition of $HI$ to the double bond of propene gives isopropyl iodide as the major product because the addition proceeds through:

For the synthesis of $but-1-ene$,$CH_3MgI$ should be treated with:

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