The major product formed in the following rea | vedclass

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(C) The reaction proceeds as follows:$(i)$ $Sn/HCl$ reduces the $-NO_2$ group to an $-NH_2$ group,forming $p$-toluidine.(ii) $Br_2$ $(1 \ eq.)$ in the

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$1-$methyl$-3,4-$dibromobenzene

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(C) The reaction proceeds as follows:$(i)$ $Sn/HCl$ reduces the $-NO_2$ group to an $-NH_2$ group,forming $p$-toluidine.(ii) $Br_2$ $(1 \ eq.)$ in the presence of the strongly activating $-NH_2$ group leads to ortho-bromination,yielding $2$-bromo-$4$-methylaniline.(iii) $NaNO_2/HCl$ at $273-278 \ K$ converts the $-NH_2$ group into a diazonium salt,$-N_2^+Cl^-$.(iv) $Cu_2Br_2/HBr$ (Sandmeyer reaction) replaces the diazonium group with a $-Br$ atom,resulting in $1,2$-dibromo-$4$-methylbenzene (also known as $3,4$-dibromotoluene).

The major product formed in the following reaction is:

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The increasing order of $pK_b$ for the following compounds will be:
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Identify $X$ and $Y$ in the following reactions:
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Nitrobenzene on reduction by zinc and $NH_4Cl$ gives

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