The major product of the following reaction i | vedclass

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Question

(D) The reaction proceeds in two steps:$1$. Formation of the Grignard reagent: Bromocyclohexene reacts with $Mg$ in the presence of dry ether to form

Vedclass · Accepted Answer

Cyclohexene with a $-D$ group attached to the double bond.

Vedclass · Answer

(D) The reaction proceeds in two steps:$1$. Formation of the Grignard reagent: Bromocyclohexene reacts with $Mg$ in the presence of dry ether to form cyclohex$-1-$enylmagnesium bromide $(C_6H_9MgBr)$.$2$. Reaction with heavy water $(D_2O)$: The Grignard reagent acts as a strong nucleophile and reacts with $D_2O$ to replace the $-MgBr$ group with a deuterium atom $(-D)$.The overall reaction is: $C_6H_9Br + Mg$ $\xrightarrow{	ext{dry ether}} C_6H_9MgBr$ $\xrightarrow{D_2O} C_6H_9D$.

The major product of the following reaction is:

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