The major product of the following reaction i | vedclass

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Question

(A) The reaction of propene with $HBr$ in the presence of benzoyl peroxide $((C_6H_5CO)_2O_2)$ proceeds via a free radical mechanism.This is known as

Vedclass · Accepted Answer

$CH_3 - CH_2 - CH_2 - Br$

Vedclass · Answer

(A) The reaction of propene with $HBr$ in the presence of benzoyl peroxide $((C_6H_5CO)_2O_2)$ proceeds via a free radical mechanism.This is known as the Kharasch effect or Peroxide effect.According to this effect,the addition of $HBr$ to an unsymmetrical alkene follows Anti-Markovnikov's rule.Therefore,the bromine atom attaches to the carbon atom with the greater number of hydrogen atoms.The reaction is: $CH_3 - CH = CH_2 + HBr \xrightarrow{Peroxide} CH_3 - CH_2 - CH_2 - Br$ ($1$-bromopropane).Thus,the correct option is $A$.

The major product of the following reaction is $CH_3 - CH = CH_2 + HBr \xrightarrow{(C_6H_5CO)_2O_2}$

Similar Questions

Amongst the following,the major product of the given chemical reaction is $.....$ .

The major product formed in the following reaction is :

$CH_2 = CH_2 \xrightarrow[KOH/H_2O]{KMnO_4} X = ......$

For the following reactions,the major products are shown: $H_2C=CH-CH=CH_2$ $\xrightarrow[0^\circ C]{HBr} CH_2=CH-CH(Br)-CH_3$ $\xrightarrow{25^\circ C} Br-CH_2-CH=CH-CH_3$. These provide an example of $1$ control at low temperature and $2$ control at higher temperature.

How many products will be formed in this reaction?

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