The major product of the following reaction i | vedclass

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(B) The reaction is the electrophilic addition of $HBr$ to $1-phenylpropene$ $(Ph-CH=CH-CH_3)$.According to Markovnikov's rule,the electrophile $(H^+)

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$Ph-CH(Br)-CH_2-CH_3$

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(B) The reaction is the electrophilic addition of $HBr$ to $1-phenylpropene$ $(Ph-CH=CH-CH_3)$.According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon atom of the double bond that has more hydrogen atoms,resulting in the formation of the most stable carbocation.In $Ph-CH=CH-CH_3$,the carbocation formed at the benzylic position $(Ph-CH^+-CH_2-CH_3)$ is highly stabilized by resonance with the phenyl ring.Therefore,the bromide ion $(Br^-)$ attacks this benzylic carbocation to form $1-phenyl-1-bromopropane$ $(Ph-CH(Br)-CH_2-CH_3)$ as the major product.

The major product of the following reaction is:

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