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(A) Step $1$: Hydrolysis of the starting material. The starting material is $4$-methoxyphenyl acetate. Treatment with $dil. \ HCl$ and heat causes hyd

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(A) Step $1$: Hydrolysis of the starting material. The starting material is $4$-methoxyphenyl acetate. Treatment with $dil. \ HCl$ and heat causes hydrolysis of the ester group,yielding $4$-methoxyphenol.Step $2$: Polymerization. The $4$-methoxyphenol is then reacted with oxalic acid $(COOH)_2$. This is a condensation polymerization reaction where the phenolic $-OH$ groups react with the carboxylic acid groups of oxalic acid to form a polyester linkage. The resulting polymer contains the $4$-methoxyphenyl unit linked via ester bonds.

The major product of the following reaction is:

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