The marks obtained (out of $25$ marks) by $40$ students in an examination are as given below:
$\begin{array}{rrrrrrrrrr} 8, & 12, & 23, & 9, & 5, & 20, & 16, & 3, & 6, & 23 \\ 10, & 6, & 21, & 1, & 18, & 17, & 18, & 16, & 16, & 12, \\ 3, & 15, & 21, & 7, & 12, & 5, & 2, & 7, & 13, & 24, \\ 13, & 18, & 8, & 2, & 20, & 5, & 13, & 7, & 23, & 16 \end{array}$
Represent the data given above by a grouped frequency distribution table,taking the class intervals as $0-5, 5-10, \dots$ etc.

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(N/A) To construct the grouped frequency distribution table,we count the number of students falling into each class interval. Note that the upper limit of each class is excluded (e.g.,$5$ is counted in $5-10$,not $0-5$).
$1$. $0-5$: $1, 2, 2, 3, 3$ (Frequency: $5$)
$2$. $5-10$: $5, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9$ (Frequency: $11$)
$3$. $10-15$: $10, 12, 12, 12, 13, 13, 13$ (Frequency: $7$)
$4$. $15-20$: $15, 16, 16, 16, 16, 17, 18, 18, 18$ (Frequency: $9$)
$5$. $20-25$: $20, 20, 21, 21, 23, 23, 23, 24$ (Frequency: $8$)
Total frequency: $5 + 11 + 7 + 9 + 8 = 40$.
Marks (Class Interval)Number of Students (Frequency)
$0-5$$5$
$5-10$$11$
$10-15$$7$
$15-20$$9$
$20-25$$8$

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