The mass and energy equivalent to 1, a.m.u. a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1\, amu$ is defined as one-twelfth of the mass of an unbound neutral atom of carbon-$12$ in its nuclear and electronic ground state.Mass of $1$ m

Vedclass · Accepted Answer

$1.67 	imes 10^{-27}\,kg, 930\, MeV$

Vedclass · Answer

(B) $1\, amu$ is defined as one-twelfth of the mass of an unbound neutral atom of carbon-$12$ in its nuclear and electronic ground state.Mass of $1$ mole of $C$ atoms $= 12\, g = 0.012\, kg$.$1\, amu = \frac{0.012\, kg}{6.023 	imes 10^{23}} \approx 1.66 	imes 10^{-27}\, kg$.Using Einstein's mass-energy equivalence formula,$E = mc^2$:$E = (1.66 	imes 10^{-27}\, kg) 	imes (3 	imes 10^8\, m/s)^2 = 1.494 	imes 10^{-10}\, J$.Converting Joules to $MeV$ $(1\, eV = 1.602 	imes 10^{-19}\, J)$:$E = \frac{1.494 	imes 10^{-10}}{1.602 	imes 10^{-13}}\, MeV \approx 931.5\, MeV \approx 930\, MeV$.Thus,the correct option is $B$.

The mass and energy equivalent to $1\, a.m.u.$ are respectively:

Similar Questions

The energy released in a nuclear reaction is due to:

Nuclear fission is possible because the binding energy per nucleon ...

The binding energy per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. The energy $Q$ released in the following reaction is:
$_1H^2 + _1H^2 \rightarrow {_2}{He}^4 + Q$

Let $m_p$ be the mass of a proton,$m_n$ the mass of a neutron,$M_1$ the mass of a ${}_{10}^{20}Ne$ nucleus,and $M_2$ the mass of a ${}_{20}^{40}Ca$ nucleus. Then:

The atomic mass of ${ }_{6} C^{12}$ is $12.000000 \ u$ and that of ${ }_{6} C^{13}$ is $13.003354 \ u$. The required energy to remove a neutron from ${ }_{6} C^{13}$,if the mass of a neutron is $1.008665 \ u$,will be: (in $MeV$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module