The mass and volume of a body are 4.237 g an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Density $\rho$ is given by the formula $\rho = \frac{m}{V}$.Given mass $m = 4.237 \ g$ (which has $4$ significant figures).Given volume $V = 2.5 \

Vedclass · Accepted Answer

$1.7$

Vedclass · Answer

(B) Density $\rho$ is given by the formula $\rho = \frac{m}{V}$.Given mass $m = 4.237 \ g$ (which has $4$ significant figures).Given volume $V = 2.5 \ cm^3$ (which has $2$ significant figures).Calculating the density: $\rho = \frac{4.237}{2.5} = 1.6948 \ g \ cm^{-3}$.According to the rules of significant figures,the result of division should have the same number of significant figures as the measurement with the fewest significant figures.Since $2.5$ has $2$ significant figures,the final answer must be rounded to $2$ significant figures.Rounding $1.6948$ to $2$ significant figures gives $1.7 \ g \ cm^{-3}$.

The mass and volume of a body are $4.237 \ g$ and $2.5 \ cm^3$,respectively. The density of the material of the body in correct significant figures is $:-$ (in $g \ cm^{-3}$)

Similar Questions

What is the number of significant figures in $0.310 \times 10^3$?

$A$ person measures the mass of $3$ different particles as $435.42 \ g$,$226.3 \ g$,and $0.125 \ g$. According to the rules for arithmetic operations with significant figures,the sum of the masses of the $3$ particles will be: (in $g$)

If the side length of a cube is $7.203 \ m$,then its volume is ............ $m^3$.

Taking into account the significant figures,what is the value of $9.99\, m - 0.0099\, m$ (in $, m$)?

Explain: "By using significant digits,we can prevent unnecessarily long calculations."

Vedclass Test Series

Exam Paper Generator

Online Exam Module