(C) Given: Mass $m = 1 \ kg$,Period $T = \frac{\pi}{2} \ s$,Displacement $x = 0.2 \ m$. Angular frequency $\omega = \frac{2\pi}{T} = \frac{2\pi}{\pi/2

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(C) Given: Mass $m = 1 \ kg$,Period $T = \frac{\pi}{2} \ s$,Displacement $x = 0.2 \ m$. Angular frequency $\omega = \frac{2\pi}{T} = \frac{2\pi}{\pi/2} = 4 \ rad/s$. Potential energy $U$ of a simple harmonic oscillator is given by $U = \frac{1}{2} kx^2$. Since $k = m\omega^2$,we have $U = \frac{1}{2} m\omega^2 x^2$. Substituting the values: $U = \frac{1}{2} \times 1 \times (4)^2 \times (0.2)^2$. $U = \frac{1}{2} \times 16 \times 0.04 = 8 \times 0.04 = 0.32 \ J$.

Class 11 Physics Oscillations Energy of Simple Harmonic Motion

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The mass of a particle is $1 \ kg$ and it is moving along the $x$-axis. The period of its oscillation is $\frac{\pi}{2} \ s$. Its potential energy at a displacement of $0.2 \ m$ is (in $J$)

AP EAMCET 2024 All AP EAMCET

A
$0.24$
B
$0.48$
C
$0.32$
D
$0.16$

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The mass of a particle is $1 \ kg$ and it is moving along the $x$-axis. The period of its oscillation is $\frac{\pi}{2} \ s$. Its potential energy at a displacement of $0.2 \ m$ is (in $J$)

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