The mass of a planet is frac{1}{10} that of t | vedclass

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(C) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.Let the mass and radius of the earth be $M$ and $R$ re

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$3.92$

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(C) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.Let the mass and radius of the earth be $M$ and $R$ respectively. Then $g = \frac{GM}{R^2} = 9.8 \ m \ s^{-2}$.For the given planet,the mass $M' = \frac{M}{10}$ and the radius $R' = \frac{R}{2}$ (since diameter is half,radius is also half).The acceleration due to gravity on the planet is $g' = \frac{GM'}{R'^2}$.Substituting the values: $g' = \frac{G(M/10)}{(R/2)^2} = \frac{GM/10}{R^2/4} = \frac{4}{10} \frac{GM}{R^2}$.Since $\frac{GM}{R^2} = 9.8 \ m \ s^{-2}$,we have $g' = 0.4 	imes 9.8 \ m \ s^{-2} = 3.92 \ m \ s^{-2}$.

The mass of a planet is $\frac{1}{10}$ that of the earth and its diameter is half that of the earth. The acceleration due to gravity on that planet is: (in $m \ s^{-2}$)

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