The mass of the planet Jupiter is 1.9 times 1 | vedclass

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(D) Given:Mass of Jupiter,$M_1 = 1.9 	imes 10^{27} \, kg$Mass of Sun,$M_2 = 1.99 	imes 10^{30} \, kg$Distance between Jupiter and Sun,$r = 7.8 	ime

Vedclass · Accepted Answer

$4.4 	imes 10^{23} \, N$

Vedclass · Answer

(D) Given:Mass of Jupiter,$M_1 = 1.9 	imes 10^{27} \, kg$Mass of Sun,$M_2 = 1.99 	imes 10^{30} \, kg$Distance between Jupiter and Sun,$r = 7.8 	imes 10^{11} \, m$Gravitational constant,$G = 6.67 	imes 10^{-11} \, N \cdot m^2 \cdot kg^{-2}$Using the universal law of gravitation formula,$F = \frac{G M_1 M_2}{r^2}$:$F = \frac{6.67 	imes 10^{-11} 	imes 1.9 	imes 10^{27} 	imes 1.99 	imes 10^{30}}{(7.8 	imes 10^{11})^2}$$F = \frac{6.67 	imes 1.9 	imes 1.99 	imes 10^{46}}{60.84 	imes 10^{22}}$$F \approx 4.146 	imes 10^{23} \, N$Rounding to the nearest provided option,the gravitational force is $4.4 	imes 10^{23} \, N$.

The mass of the planet Jupiter is $1.9 \times 10^{27} \, kg$ and that of the Sun is $1.99 \times 10^{30} \, kg$. The mean distance of the Sun from Jupiter is $7.8 \times 10^{11} \, m$. Calculate the gravitational force which the Sun exerts on Jupiter.

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