State whether the following statement is True or False:
The value of $g$ is zero at the centre of the earth.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(TRUE) The statement is True.
According to the formula for acceleration due to gravity at a depth $d$ below the surface of the Earth,$g_d = g(1 - d/R)$,where $g$ is the acceleration due to gravity at the surface,$d$ is the depth,and $R$ is the radius of the Earth.
At the centre of the Earth,the depth $d$ is equal to the radius $R$ $(d = R)$.
Substituting $d = R$ into the formula,we get $g_d = g(1 - R/R) = g(1 - 1) = g(0) = 0$.
Therefore,the acceleration due to gravity $(g)$ at the centre of the Earth is zero.

Explore More

Similar Questions

Will a body weigh more on the equator or at the poles?

$(i)$ Seema buys a few grains of gold at the poles as per the instructions of one of her friends. She hands over the same when she meets her at the equator. Will the friend agree with the weight of gold bought? If not,why?
$(ii)$ If the moon attracts the earth,why does the earth not move towards the moon?

$A$ planet existed whose mass and radius were both half of the Earth. What would be the acceleration due to gravity at the surface of the planet in terms of that on the surface of the Earth?

Calculate the force of gravitation between two objects of masses $50 \, kg$ and $120 \, kg$ respectively,kept at a distance of $10 \, m$ from each other. $(G = 6.673 \times 10^{-11} \, N \, m^2 \, kg^{-2})$

Give reason: $A$ stone falls towards the earth,but the earth does not rise towards the stone.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo