The maximum energy in the thermal radiation f | vedclass

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(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\la

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$0.5$

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(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\lambda_{1} = 11 	imes 10^{-5} 	ext{ cm}$ and $\lambda_{2} = 5.5 	imes 10^{-5} 	ext{ cm}$.We are given $T_{1} = n T_{2}$.Substituting these values into the equation: $(11 	imes 10^{-5}) 	imes (n T_{2}) = (5.5 	imes 10^{-5}) 	imes T_{2}$.Dividing both sides by $T_{2}$ and $10^{-5}$,we get $11n = 5.5$.Thus,$n = \frac{5.5}{11} = 0.5$.

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