The maximum velocity of a particle performing $S.H.M.$ is $V$. If the periodic time is made $\left(\frac{1}{3}\right)^{rd}$ of its original value and the amplitude is doubled,then the new maximum velocity of the particle will be:

  • A
    $\frac{V}{6}$
  • B
    $\frac{3V}{2}$
  • C
    $3V$
  • D
    $6V$

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