The maximum velocity of the photoelectron emitted by the metal surface is $V$. The charge and mass of the photoelectron are denoted by $e$ and $m$,respectively. The stopping potential in volts is:

  • A
    $\frac{V^2}{2(m/e)}$
  • B
    $\frac{m V^2}{2 e}$
  • C
    $\frac{V^2}{(e/m)}$
  • D
    $\frac{V^2}{(m/e)}$

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