The mean deviation about the median for the f | vedclass

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(B) The given data is $6, 3, 4, 9, 2, 7, 11$. First,arrange the data in ascending order: $2, 3, 4, 6, 7, 9, 11$. There are $n = 7$ observations,which

Vedclass · Accepted Answer

$2.57$

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(B) The given data is $6, 3, 4, 9, 2, 7, 11$. First,arrange the data in ascending order: $2, 3, 4, 6, 7, 9, 11$. There are $n = 7$ observations,which is odd. The median $M$ is the $\left(\frac{n+1}{2}\right)^{th}$ observation,which is the $4^{th}$ observation. Thus,$M = 6$. The mean deviation about the median is given by $\frac{1}{n} \sum_{i=1}^{n} |x_i - M|$. Mean deviation $= \frac{1}{7} [|2-6| + |3-6| + |4-6| + |6-6| + |7-6| + |9-6| + |11-6|]$. Mean deviation $= \frac{1}{7} [|-4| + |-3| + |-2| + 0 + |1| + |3| + |5|]$. Mean deviation $= \frac{1}{7} [4 + 3 + 2 + 0 + 1 + 3 + 5] = \frac{18}{7} \approx 2.57$.

The mean deviation about the median for the following data $6, 3, 4, 9, 2, 7, 11$ is

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