The mean deviation about the median of the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the mean deviation about the median,we first calculate the cumulative frequency $(c.f.)$:$x$$f$$c.f.$$|x_i - 	ext{Median}|$$f_i |x_i -

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

(A) To find the mean deviation about the median,we first calculate the cumulative frequency $(c.f.)$:$x$$f$$c.f.$$|x_i - 	ext{Median}|$$f_i |x_i - 	ext{Median}|$$6$$4$$4$$18$$72$$12$$7$$11$$12$$84$$18$$9$$20$$6$$54$$24$$18$$38$$0$$0$$30$$15$$53$$6$$90$$36$$10$$63$$12$$120$$42$$5$$68$$18$$90$Total frequency $N = \Sigma f_i = 68$.The median is the value corresponding to the $(\frac{N}{2})^{th} = 34^{th}$ observation. From the $c.f.$ column,the $34^{th}$ observation lies in the class where $x = 24$.So,$	ext{Median} = 24$.The mean deviation about the median is given by:$	ext{M.D.}(	ext{Median}) = \frac{\Sigma f_i |x_i - 	ext{Median}|}{\Sigma f_i} = \frac{72 + 84 + 54 + 0 + 90 + 120 + 90}{68} = \frac{510}{68} = 7.5$.

Marks obtained	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
No of students	$2$	$3$	$8$	$14$	$8$	$3$	$2$

The mean deviation about the median of the following distribution is:
$x$ $6$ $12$ $18$ $24$ $30$ $36$ $42$
$f$ $4$ $7$ $9$ $18$ $15$ $10$ $5$

Similar Questions

Find the mean deviation about the mean for the following data: $12, 3, 18, 17, 4, 9, 17, 19, 20, 15, 8, 17, 2, 3, 16, 11, 3, 1, 0, 5$.

If the mean deviation about the median of the numbers $a, 2a, 3a, \dots, 50a$ is $50$,then $|a|$ equals:

Find the mean deviation about the mean for the following data.
Marks obtained $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
No of students $2$ $3$ $8$ $14$ $8$ $3$ $2$

The following data represents the frequency distribution of $20$ observations.
$x_i$ $3$ $4$ $5$ $8$ $10$ $11$
$f_i$ $\alpha+2$ $(\alpha-1)^2$ $4$ $\alpha-1$ $2$ $\alpha$
Then its mean deviation about the mean is

The mean deviation about the mean for the data $4, 7, 8, 9, 10, 12, 13, 17$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The mean deviation about the median of the following distribution is:$x$$6$$12$$18$$24$$30$$36$$42$$f$$4$$7$$9$$18$$15$$10$$5$