The mean deviation from the median for the fo | vedclass

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(C) First,we arrange the data in ascending order and calculate the cumulative frequency $(cf)$: $x_i: 2, 3, 5, 7, 9$ $f_i: 8, 6, 4, 2, 1$ $cf: 8, 14,

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$\frac{10}{7}$

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(C) First,we arrange the data in ascending order and calculate the cumulative frequency $(cf)$: $x_i: 2, 3, 5, 7, 9$ $f_i: 8, 6, 4, 2, 1$ $cf: 8, 14, 18, 20, 21$ Total frequency $N = \sum f_i = 21$. The median is the value corresponding to the $(\frac{N+1}{2})$-th observation,which is the $11$-th observation. From the $cf$ table,the $11$-th observation is $3$. So,$	ext{Median} (M) = 3$. Now,calculate the mean deviation about the median: $	ext{M.D.}(M) = \frac{\sum f_i |x_i - M|}{N}$ $|x_i - 3|: |2-3|=1, |3-3|=0, |5-3|=2, |7-3|=4, |9-3|=6$ $f_i |x_i - 3|: 8(1)=8, 6(0)=0, 4(2)=8, 2(4)=8, 1(6)=6$ $\sum f_i |x_i - 3| = 8 + 0 + 8 + 8 + 6 = 30$ $	ext{M.D.}(M) = \frac{30}{21} = \frac{10}{7}$.

$x_i$	$3$	$6$	$9$	$12$	$13$	$15$	$21$	$22$
$f_i$	$3$	$4$	$5$	$2$	$4$	$5$	$4$	$3$

$x_i$	$5$	$7$	$9$	$10$	$12$	$15$
$f_i$	$8$	$6$	$2$	$2$	$2$	$6$

The mean deviation from the median for the following data is
$x_i$ $2$ $3$ $5$ $7$ $9$
$f_i$ $8$ $6$ $4$ $2$ $1$

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is equal to: (in /$13$)

If the mean deviation from the mean of the observations $\{1+K \alpha\}$,where $K=0, 1, 2, \ldots, 100$ and $\alpha > 0$ is $255$,then $\alpha =$

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The mean deviation from the median for the following data is $x_i$$2$$3$$5$$7$$9$$f_i$$8$$6$$4$$2$$1$