The mean of 100 observations is 50 and their | vedclass

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(A) We know that the formula for standard deviation $\sigma$ is given by: $\sigma^2 = \frac{\Sigma x_i^2}{n} - (\bar{x})^2$ Given: $n = 100$ $\bar{x}

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$252500$

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(A) We know that the formula for standard deviation $\sigma$ is given by: $\sigma^2 = \frac{\Sigma x_i^2}{n} - (\bar{x})^2$ Given: $n = 100$ $\bar{x} = 50$ $\sigma = 5$ Substituting the values: $5^2 = \frac{\Sigma x_i^2}{100} - (50)^2$ $25 = \frac{\Sigma x_i^2}{100} - 2500$ $\frac{\Sigma x_i^2}{100} = 2500 + 25 = 2525$ $\Sigma x_i^2 = 2525 	imes 100 = 252500$ Thus,the sum of squares of all observations is $252500$.

The mean of $100$ observations is $50$ and their standard deviation is $5$. Then,the sum of squares of all observations is

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