The minimum magnifying power of a telescope i | vedclass

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(B) The magnifying power $(m)$ of an astronomical telescope in normal adjustment is given by the formula $m = -\frac{f_o}{f_e}$, where $f_o$ is the fo

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$2M$

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(B) The magnifying power $(m)$ of an astronomical telescope in normal adjustment is given by the formula $m = -\frac{f_o}{f_e}$, where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eye lens.From this relation, it is clear that the magnifying power is inversely proportional to the focal length of the eye lens: $m \propto \frac{1}{f_e}$.If the focal length of the eye lens is halved, i.e., $f_e' = \frac{f_e}{2}$, the new magnifying power $m'$ becomes:$m' = -\frac{f_o}{f_e'} = -\frac{f_o}{f_e / 2} = 2 \left( -\frac{f_o}{f_e} \right) = 2M$.Therefore, the magnifying power becomes $2M$.

The minimum magnifying power of a telescope is $M$. If the focal length of its eye lens is halved, the magnifying power will become:

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