The mole fraction of ethanol in water is 0.08 | vedclass

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Question

(B) Given: Mole fraction of ethanol $(x_{EtOH})$ = $0.08$. Since the sum of mole fractions is $1$, the mole fraction of water $(x_{H_2O})$ = $1 - 0.08

Vedclass · Accepted Answer

$4.83 \ mol \ kg^{-1}$

Vedclass · Answer

(B) Given: Mole fraction of ethanol $(x_{EtOH})$ = $0.08$. Since the sum of mole fractions is $1$, the mole fraction of water $(x_{H_2O})$ = $1 - 0.08 = 0.92$. Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent. The formula relating molality to mole fraction is: $m = \frac{x_{solute}}{x_{solvent}} 	imes \frac{1000}{MW_{solvent}}$ Substituting the values: $m = \frac{0.08}{0.92} 	imes \frac{1000}{18.02} \approx 4.83 \ mol \ kg^{-1}$.

The mole fraction of ethanol in water is $0.08$. Its molality is

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