When 6 g of urea is dissolved in 180 g of H | vedclass

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(D) The molar mass of urea $(NH_2CONH_2)$ is $60 \ g/mol$. The number of moles of urea $(n) = \frac{6 \ g}{60 \ g/mol} = 0.1 \ mol$. The molar mass of

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$\frac{0.1}{10.1}$

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(D) The molar mass of urea $(NH_2CONH_2)$ is $60 \ g/mol$. The number of moles of urea $(n) = \frac{6 \ g}{60 \ g/mol} = 0.1 \ mol$. The molar mass of water $(H_2O)$ is $18 \ g/mol$. The number of moles of water $(N) = \frac{180 \ g}{18 \ g/mol} = 10 \ mol$. The mole fraction of urea $(X_{urea})$ is given by the formula: $X_{urea} = \frac{n}{n + N}$. Substituting the values: $X_{urea} = \frac{0.1}{0.1 + 10} = \frac{0.1}{10.1}$.

When $6 \ g$ of urea is dissolved in $180 \ g$ of $H_2O$,the mole fraction of urea is:

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