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(B) The formation of cyanohydrin involves a nucleophilic addition reaction to the carbonyl group. The reactivity depends on the electrophilicity of th

Vedclass · Accepted Answer

$p-$Nitrobenzaldehyde

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(B) The formation of cyanohydrin involves a nucleophilic addition reaction to the carbonyl group. The reactivity depends on the electrophilicity of the carbonyl carbon. Electron-withdrawing groups increase the partial positive charge on the carbonyl carbon,making it more susceptible to nucleophilic attack by the $CN^-$ ion. Among the given options,the $-NO_2$ group in $p-$nitrobenzaldehyde is a strong electron-withdrawing group,which significantly increases the electrophilicity of the carbonyl carbon compared to the other substituents. Therefore,$p-$nitrobenzaldehyde is the most reactive compound towards cyanohydrin formation.

The most reactive compound towards the formation of cyanohydrin on treatment with $KCN$ followed by acidification is:

Similar Questions

Which of the following pairs of reactants is most effective in forming an enamine?

The product $(A)$ is:

Predict the product of the following reaction:
$3$-hydroxycyclopentanone $\xrightarrow{Zn-Hg/HCl}$ product

What are $X$ and $Y$ respectively in the following reaction sequence?

Assertion $(A)$: Ammonia and its derivatives of the form $H_2N-Z$ undergo condensation reaction with carbonyl compounds (aldehydes and ketones).
Reason $(R)$: This reaction is an example of an irreversible reaction.
The correct option among the following is:

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