(C) The person is suffering from hypermetropia (farsightedness) because the near point has shifted from the normal $25\,cm$ to $40\,cm$.To read a book

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(C) The person is suffering from hypermetropia (farsightedness) because the near point has shifted from the normal $25\,cm$ to $40\,cm$.To read a book at $u = -25\,cm$,the lens must form a virtual image at the person's near point,$v = -40\,cm$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $P = \frac{1}{-0.4} - \frac{1}{-0.25}$.$P = -2.5 + 4.0 = 1.5\,D$.Thus,the required power of the lens is $1.5\,D$.

Class 12 Physics Ray Optics and Optical Instruments Human Eye and Defects of Vision

Medium

The near point and far point of a person are $40\,cm$ and $250\,cm$ respectively. Determine the power of the lens he/she should use while reading a book kept at a distance of $25\,cm$ from the eye $..........D$

AIIMS 2015 All AIIMS

A
$2.5$
B
$5.0$
C
$1.5$
D
$3.5$

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Class 12 Questions

Class 12

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Chapter

Ray Optics and Optical Instruments

Subtopic

Human Eye and Defects of Vision

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AIIMS 2015 Paper All AIIMS years →

$A$ man can see only between $75 \, cm$ and $100 \, cm$. The power of the lens required to correct the near point will be:

Medium

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$A$ person with hypermetropia has a near point of $60\, cm$. What power of lens should be used for the eye to read a book at $25\, cm$?

Medium

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The least distance of distinct vision for a farsighted person is $1 \ m$. The optical power of the lens of his spectacles,which effectively reduces his least distance of distinct vision $(LDDV)$ to $25 \ cm$,is:

Medium

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The image formed on the retina of the eye is proportional to:

Easy

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$A$ man who cannot see clearly beyond $5 \, m$ wants to see stars clearly. He should use a lens of focal length ....... $m$.

Medium

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The near point and far point of a person are $40\,cm$ and $250\,cm$ respectively. Determine the power of the lens he/she should use while reading a book kept at a distance of $25\,cm$ from the eye $..........D$

Similar Questions

$A$ man can see only between $75 \, cm$ and $100 \, cm$. The power of the lens required to correct the near point will be:

$A$ person with hypermetropia has a near point of $60\, cm$. What power of lens should be used for the eye to read a book at $25\, cm$?

The least distance of distinct vision for a farsighted person is $1 \ m$. The optical power of the lens of his spectacles,which effectively reduces his least distance of distinct vision $(LDDV)$ to $25 \ cm$,is:

The image formed on the retina of the eye is proportional to:

$A$ man who cannot see clearly beyond $5 \, m$ wants to see stars clearly. He should use a lens of focal length ....... $m$.

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