The negation of the converse of the statement | vedclass

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(A) $1$. The given statement is $p \lor q$. $2$. The converse of a statement $p \implies q$ is $q \implies p$. However, for a simple disjunction $p \l

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$\sim p \land \sim q$

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(A) $1$. The given statement is $p \lor q$. $2$. The converse of a statement $p \implies q$ is $q \implies p$. However, for a simple disjunction $p \lor q$, the converse is defined as $q \lor p$. $3$. Since $p \lor q$ is logically equivalent to $q \lor p$ (commutative law), the converse of $p \lor q$ is $p \lor q$ itself. $4$. The negation of $p \lor q$ is $\sim(p \lor q)$. $5$. By De Morgan's Law, $\sim(p \lor q) \equiv \sim p \land \sim q$.

The negation of the converse of the statement $p \lor q$ is:

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