The net gain of ATP molecules during aerobic | vedclass

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Question

(B) During aerobic respiration,one molecule of glucose undergoes glycolysis,the Krebs cycle,and the electron transport system $(ETS)$.$1$. Glycolysis

Vedclass · Accepted Answer

$38$

Vedclass · Answer

(B) During aerobic respiration,one molecule of glucose undergoes glycolysis,the Krebs cycle,and the electron transport system $(ETS)$.$1$. Glycolysis produces $2$ $ATP$ and $2$ $NADH$.$2$. The link reaction produces $2$ $NADH$.$3$. The Krebs cycle produces $2$ $ATP$ (or $GTP$),$6$ $NADH$,and $2$ $FADH_2$.Total $NADH$ produced is $10$ ($2$ from glycolysis,$2$ from link reaction,$6$ from Krebs cycle). Each $NADH$ yields $3$ $ATP$ (total $30$ $ATP$).Total $FADH_2$ produced is $2$ (from Krebs cycle). Each $FADH_2$ yields $2$ $ATP$ (total $4$ $ATP$).Total $ATP$ = $2$ (glycolysis) + $2$ (Krebs) + $30$ $(NADH)$ + $4$ $(FADH_2)$ = $38$ $ATP$.However,in many eukaryotic cells,the shuttle mechanism (like the glycerol-phosphate shuttle) consumes $2$ $ATP$ to transport $NADH$ into the mitochondria,resulting in a net gain of $36$ $ATP$. In prokaryotes,the net gain is $38$ $ATP$. Given the standard textbook context for general aerobic respiration,$38$ is the theoretical maximum,but $36$ is often cited for eukaryotes. Since $38$ is the classic total yield,it is the standard answer.

The net gain of $ATP$ molecules during aerobic breakdown of one glucose molecule is . . . . . . .

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